This is the article about the matter of two objects of different masses are suspended by a cable of inextensible over pulley of massless. One thing here we have to remember that two objects are moved vertically with same acceleration. For two objects free body diagram is same that is like below
For the object of mass m1, unbalanced force acting on m1 is T-m1g. i.e.,
T-m1g=m1a--------1
For the object of mass m2, unbalanced force acting on m2 is m2g-T.i.e.,
m2g-T=m2a--------2
Adding equations 1 and 2, we get
From the equation 1,
According to the figure, this tension will be less than m1g and greater than m2g
No comments:
Post a Comment